Hey guys I've got a DL1000 and it's a little bumpy in the front forks. I've talked it over with someone in the know and they suggest that I remove an additional 10mm of fork oil. I'm not too excited to remove the forks again and I have a mighty-vac so I thought I would just run some tubing down and remove the oil that way but I don't know what 10mm would equal in milliliters. Anyone have an exceptional understanding of measurement that would like to chime in?

Thanks

If you want to be precise, measure the inside diameter of the fork tube after you remove the cap. An estimate of this, which I made from a picture of the fork cap in the service manual, is 38 mm, which is probably close enough. That's the value I'll use in the following calculation.

Convert mm to centimeters by moving the decimal place to the left one digit. For example, 38 mm = 3.8 cm.

Cross-sectional area of the inside of the fork is 3.8^2 * 3.14 / 4. That's 11.33 square centimeters.

Conveniently, you plan to remove 10 mm, or 1 cm. A ml is a cubic centimeter. So the volume is just 11.33 * 1, or 11.33 ml. [See note below]

If you measure the inside diameter of the fork tube, substitute that value for 38 mm (3.8 cm) in the calculation above.

Note: The volume of the rod that extends up from the cartridge probably takes up somewhere between 0.5 and 1.0 ml, so I'd reduce the volume calculated above by about 0.75 ml.

Thanks for taking the time to post up!

I've got a project for tomorrow!!!

Removing oil will only affect the final few centimeter or two, of suspension travel - namely, when you're approaching bottom out. Reducing oil volume allows for more air in the fork. More air = less of an air spring effect when the fork is approaching bottoming out. If your fork is a bit "bumpy", you're probably not bottoming out your fork, but instead, it's a bit to slow to react to sharper edged bumps. You should be really concentrating on perhaps running a lower viscosity oil to allow your fork to react quicker than it does with the 10 wt oil. I'd try a 7.5 wt.