Adding 'reverse' chain drive question - Stromtrooper Forum : Suzuki V-Strom Motorcycle Forums
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post #1 of 33 Old 04-05-2010, 07:51 PM Thread Starter
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Adding 'reverse' chain drive question

Here is a question for you ME types out there, what would be the approximate torque required for a small dc gearhead motor to drive the chain in reverse on a DL650? I'm just fantasizing, but can imagine a small motor with a sprocket that could be manually lowered (or raised) against the chain with all the proper safety interlocks (-:
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post #2 of 33 Old 04-05-2010, 08:42 PM
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Torque-wise, probably only a few foot-pounds. The 650 only has about 35 ft/lb max. However you can't do it with one gear, it will take a reduction gear set. The pinion will have to be quite small or the starting current and low-speed current will be horrendous.

The biggest question is, Why???

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post #3 of 33 Old 04-05-2010, 09:23 PM
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Quote:
Originally Posted by SCraig View Post
The biggest question is, Why???
Yeah, why?

Are you trying to fit a Wee with reverse?

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post #4 of 33 Old 04-05-2010, 10:24 PM
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He came off a GoldWing??

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post #5 of 33 Old 04-05-2010, 11:03 PM
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If you are adding a sidecar some people are buying HF winches and gutting them for a reverse gear.





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post #6 of 33 Old 04-06-2010, 01:03 AM
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The GoldWing does use the starter motor and gearing of course for its reverse. But, an 800 pound bike being pushed backwards in gravel benefits from reverse.
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post #7 of 33 Old 04-06-2010, 02:54 AM
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Hey, the guy is just asking! Sometimes the stupidest ideas lead to brilliance (I'm not saying your idea is stupid, I'm just saying).

Assumptions:
1. DL1000 wet weight = 523 lbf
2. Rider weight = 250 lbf
3. Passenger weight = 120 lbf (hey, that's what she told me)
4. Nice assortment of farkles, unpacked = 100 lbf
5. Slope angle of the hole you managed to get your front end stuck in = 5 degrees
6. Drive sprocket on the Super Deluxe V-Strom Reverse Contraption = 3" diameter (about the same size as the drive sprocket from the engine)

Shaft torque requirement for your motor will be 328 in*lbf, just to keep it static on the 5 degrees. The motor will be able to move the bike on any slope less than 5 degrees, and anything more you'll be doing the reverse shuffle with your feet to help it out.

However, sprockets can't engage and actually put power to a chain that isn't wrapped at least 120 degrees or so around the sprocket, and that's with serious tension and/or idler sprockets. The rollers want to climb out of the valleys of the sprocket when power is applied, and there's nothing stopping them with small amount of engagement. You'd need a couple of idler gears and a lot longer chain to allow it to snake its way around the reverse sprocket.

You'd be better off putting a friction wheel against the back tire. Your torque requirement would go way down. The same 3" drive (now a rubber wheel rather than a sprocket) would require about 130 in*lbf.

I think a 623-pound bike would benefit from reverse also. Maybe not to the extent of an 800-pound bike, but tell that to your 120-pound passenger as she's pushing on the front of the bike while your 250 pounds is steering it.

Edit (disclaimer): I doubt this info will ever be used, but if it is please let me know. If you're gonna use it, you should understand and take responsibility for the calculations. Therefore, make sure you either work through them yourself and verify my results or inquire how I did it.

Last edited by coveter; 04-14-2010 at 05:21 PM. Reason: Disclaimer
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post #8 of 33 Old 04-06-2010, 11:22 AM
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Talking

Now THAT is a reply. What a guy.

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post #9 of 33 Old 04-06-2010, 11:37 AM
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Kudos to coveter for doing something all-too-rarely seen on this forum: giving specific and relevant advice without indulging in second-guessing the questioner's motives, judgment or sanity.

I wish there were more good forum citizens like him.

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post #10 of 33 Old 04-06-2010, 11:44 AM
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+1 on the coveter praise. Interesting to read the info, even tho I'll never need it.
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